Conan

You have the ID of the selected SubscriptionPopupContent in the URL right? I'm thinking something like $currentSubscriptionPopupContent = $this->SubscriptionPopupContent()->find('ID', $contentIdFromUrl); (there is probably a better way)

customPhpDev

I have tried with $this->Parent()->Title but it has given me an error.

customPhpDev

I want to add a condition like, if the title is Article then, one of the fields should be hidden.

kinglozzer

If they’re many_many, it could have many titles, which one do you want?

customPhpDev

I have a data object called SubscriptionPopupContent which has a Title field. This data object has a tab called SubscriptionPopupItem whose records are in the grid. SubscriptionPopupContent has relationship many_many relationship with SubscriptionPopupItem. Now, when I click on one of the SubscriptionPopupItems, I want to have a value of Title of SubscriptionPopupContent. Can someone please help me how can I get it?

Firesphere

Also, I hate server permissions and stuff, that fucks these kind of things around for reasons

Firesphere

I would agree, that looking where the session is stored is a key thing, but /var/lib/php is not a given....

Firesphere

I'm not sure about /var/lib/session. Depending on the installation, it might be in a completely different path

brett.tasker

You can also confirm where Sessions are being written to on Prod by checking session.save_path in your php.ini file (or running php -i | grep session from CLI)